1. cambiassi
  2. General
  3. Tuesday, March 24 2015, 08:29 PM
Hello,

I want to display user ID in a column of a MENU USER LIST, I somehow thought I could manage to do so by making a delimiter field with this code:

<?php
require_once(JPATH_SITE.'/components/com_jsn/helpers/helper.php');
$id = JFactory::getApplication()->input->getInt('id', 0);
echo $id;
$user=new JsnUser($id);
echo $user->getLink();
?>


It didn't work, so I'm wondering whats the right way to do this?

Thanks.
admin Accepted Answer
Admin
Hi,
HTML delimiter field is a good way but this not parse PHP code, you can user this code:
{user id displayed raw}


Our content plugin will replace this code with id of users. docs at https://www.easy-profile.com/docs/26-plugin-content.html
  1. more than a month ago
  2. General
  3. # 1
  • Page :
  • 1


There are no replies made for this post yet.
However, you are not allowed to reply to this post.
Sorry, the discussion is currently locked. You will not be able to post a reply at the moment.